How to use JPA entity manager instead of Ivy Entity Manager?

Question

Hi everyone,

Currently, I need to set up and use the JPA entity manager not Ivy Entity Manager because our team want it to work with JUnit. (Ivy Entity Manager doesn't work with JUnit because of Ivy environment).

Is that possible to do so? I have tried edit the persistence.xml and try to create an entity manager but I've got the exception:

javax.persistence.PersistenceException: [PersistenceUnit: xrfl_unit] Unable to build EntityManagerFactory
    at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:924)
    at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:899)
    at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:59)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
    at ch.soreco.standard.xrfl.service.TransactionManager.execute(TransactionManager.java:38)
    at ch.soreco.standard.xrfl.service.ValuationService.findAll(ValuationService.java:26)
    at ch.soreco.standard.xrfl.unittest.service.ValuationServiceTest.findAll(ValuationServiceTest.java:28)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:45)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:42)
    at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
    at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
    at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:263)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:68)
    at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:47)
    at org.junit.runners.ParentRunner$3.run(ParentRunner.java:231)
    at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:60)
    at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:229)
    at org.junit.runners.ParentRunner.access$000(ParentRunner.java:50)
    at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:222)
    at org.junit.runners.ParentRunner.run(ParentRunner.java:300)
    at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
    at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
    at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
Caused by: org.hibernate.service.jndi.JndiException: Error parsing JNDI name [XRFL]
    at org.hibernate.service.jndi.internal.JndiServiceImpl.parseName(JndiServiceImpl.java:92)
    at org.hibernate.service.jndi.internal.JndiServiceImpl.locate(JndiServiceImpl.java:63)
    at org.hibernate.service.jdbc.connections.internal.DatasourceConnectionProviderImpl.configure(DatasourceConnectionProviderImpl.java:116)
    at org.hibernate.service.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:85)
    at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:184)
    at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:156)
    at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.buildJdbcConnectionAccess(JdbcServicesImpl.java:223)
    at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:89)
    at org.hibernate.service.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:85)
    at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:184)
    at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:156)
    at org.hibernate.cfg.Configuration.buildTypeRegistrations(Configuration.java:1825)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1783)
    at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:96)
    at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:914)
... 31 more
Caused by: javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file:  java.naming.factory.initial
    at javax.naming.spi.NamingManager.getInitialContext(Unknown Source)
    at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
    at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
    at javax.naming.InitialContext.getNameParser(Unknown Source)
    at org.hibernate.service.jndi.internal.JndiServiceImpl.parseName(JndiServiceImpl.java:86)
... 45 more

If you have any idea or suggestion, please share with me.

Thank You.

Answer 1

2

The interface of IIvyEntityManager makes it possible to access the "real" JPA EntityManager by invoking createEntityManager(). So code that uses it could look like this:

private static List<String> getMatchingCountries(String country){
    IIvyEntityManager ivyEntityManager = Ivy.persistence().get("PERSISTENCE_UNIT_NAME");
    EntityManager em = ivyEntityManager.createEntityManager();
    try{
        em.getTransaction().begin();

        // DO FANCY PLAIN JPA STUFF
        Query countryQuery = em.createQuery(
            "SELECT DISTINCT a.country FROM Address a " +
            "WHERE a.country LIKE :userInput");
            countryQuery.setParameter("userInput", "%"+country+"%");
        List<String> result = (List<String>) countryQuery.getResultList();

        em.getTransaction().commit();
        return result;
    }
    finally
    {
        em.close();
    }
}

link

answered 22.12.2014 at 08:53

Reguel Werme... ♦♦
9.4k●3●19●58
accept rate: 70%

Thanks for the idea but with this way, you still need the Ivy environment in order to get the EntityManager which will cause environment exception in JUnit.

(22.12.2014 at 09:14) Tran Cuong Truc

You need to mock out the Ivy class as described here: http://answers.axonivy.com/questions/617/how-can-junit-access-to-ivy-environment-without-environmentnotavailableexception

(22.12.2014 at 09:28) Reguel Werme... ♦♦

Thank you for your answer, but if you mock the Ivy class, you need to mock the .persistence().get("PERSISTENCE_UNIT_NAME") aswell. Unfortunately, I wasn't able to do that.

(18.02.2015 at 13:29) Lukas Schmid

hi @Reguel Werme... ♦♦ Is there any way to overcome this issue? i also want to create Java persistence manager for Junit inside java. Thanks

(02.02.2018 at 04:25) trungdv

How to use JPA entity manager instead of Ivy Entity Manager?

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